Find an equation of the circle tangent to the lines x=1, x=9, y=0
Accepted Solution
A:
Answer:(x − 5)² + (y − 4)² = 4²(x − 5)² + (y + 4)² = 4²Step-by-step explanation:x=1 and x=9 are vertical lines. If both are tangent to the circle, then the circle has a diameter of 8, or a radius of 4, and the center of the circle is on the line x=5.y=0 is the x-axis. Since the circle is tangent to that, the center of the circle is either 4 units above the x-axis or 4 units below.So two possible equations of the circle are:(x − 5)² + (y − 4)² = 4²(x − 5)² + (y + 4)² = 4²Here's a graph: desmos.com/calculator/9e4lxx731u